LSAT Blog - PrepTest 73 Logic Game 2 - Speakers in Gold / Rose Rooms (September 2014 LSAT) - evolve-gaming.com

LSAT Blog – PrepTest 73 Logic Game 2 – Speakers in Gold / Rose Rooms (September 2014 LSAT)

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This is LSAT Blog’s explanation for LSAT PrepTest 73 Logic Game 2. It’s the game about Speakers in Gold / Rose Rooms from the September 2014 LSAT.

Long, Molina, Xiao, Yoshida, Zimmerman

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3 Comments

  1. I'm confused.. For question # 10 both A and B could be the right answer. Can somebody show me why B can't be correct please?

  2. Hi, thanks for the video. I have a question about setting up the contrapositive for rule #3; how can you guarantee that the contrapositive for rule #3 is valid? Maybe I'm missing something, but how does X or Z being in the Gold Room guarantee that M & L would be in the Rose Room? Thanks again.

  3. I am still unclear about question 10. In the setup and rules, specifically rules 1 and 3, we know that M is always with and before L.

    In rule 3 it says that if L (ML) is in G, X and Z are in R.

    So, if L (ML) is in R, Z, and X are in G.

    Because of this, how can M, L, AND X be in the same room in diagram 3?

    I understand that in the setup it says that it is undetermined which room will have the speech at 3, but it seems like with this question and all the choices, the only way to answer the question is to just ignore a rule without ever being told to do so.

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